Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Bu | 489 | 28 | 2 | 14.0000 |
Cumhurbaşkanı | 87 | 8 | 1 | 8.0000 |
şu | 104 | 8 | 1 | 8.0000 |
O | 80 | 6 | 1 | 6.0000 |
ikinci | 64 | 6 | 1 | 6.0000 |
Son | 101 | 5 | 1 | 5.0000 |
ortaya | 96 | 5 | 1 | 5.0000 |
mağlup | 34 | 5 | 1 | 5.0000 |
5 | 100 | 5 | 1 | 5.0000 |
uzun | 53 | 5 | 1 | 5.0000 |
güvenlik | 50 | 5 | 1 | 5.0000 |
sahip | 74 | 5 | 1 | 5.0000 |
milyar | 69 | 5 | 1 | 5.0000 |
yurt | 27 | 5 | 1 | 5.0000 |
ne | 193 | 9 | 2 | 4.5000 |
Türkiye | 204 | 13 | 3 | 4.3333 |
çalışmaları | 42 | 4 | 1 | 4.0000 |
zor | 40 | 4 | 1 | 4.0000 |
Rusya | 38 | 4 | 1 | 4.0000 |
dile | 53 | 4 | 1 | 4.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
edildi | 135 | 1 | 11 | 0.0909 |
verdi | 97 | 1 | 11 | 0.0909 |
bulundu | 114 | 1 | 8 | 0.1250 |
ardından | 189 | 1 | 8 | 0.1250 |
etti | 218 | 3 | 23 | 0.1304 |
şekilde | 139 | 1 | 7 | 0.1429 |
ederek | 60 | 1 | 7 | 0.1429 |
aldı | 109 | 1 | 6 | 0.1667 |
yılında | 69 | 1 | 6 | 0.1667 |
edilen | 68 | 1 | 6 | 0.1667 |
ediyor | 87 | 1 | 6 | 0.1667 |
günü | 98 | 2 | 11 | 0.1818 |
zaman | 148 | 2 | 11 | 0.1818 |
şey | 87 | 1 | 5 | 0.2000 |
farklı | 70 | 1 | 5 | 0.2000 |
göre | 273 | 4 | 17 | 0.2353 |
kullandı | 87 | 1 | 4 | 0.2500 |
sevk | 50 | 1 | 4 | 0.2500 |
an | 37 | 1 | 4 | 0.2500 |
alındı | 52 | 1 | 4 | 0.2500 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II